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*Today's Question**What is the vertical support reaction at point B of the frame?*

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Sum of Moment respect point (A)= By x 5m + 1.0 x 14m = 0 then By = -1.0 x 14 / 5 = - 2.8kN = (-14/5) or if you look at the first triangular bending moment from A to B which is equal to 9.0kNm and divide it for the lever arm which is 5m it is possible to find the reaction Ay = 1.8kN then for the equilibrium of the vertical forces let's say: Ay=1.8kN + By + X2=1.0kn = 0 then By= -2.8 or (-14/5), hence B) is correct.

ReplyDeleteB) -14/5

ReplyDeleteTotal Reaction, Ay + By = - 1 kN (let's say Equation 1)

ReplyDeleteTaking moment about B,

Ay x 5 = 1 x 9

Ay = 9/5 kN

Apply the value of Ay in Equation 1, we have

By = -1 - (9/5) = -14/5 kN

B) -14/5

MOMENT ABOUT POINT B

ReplyDelete5*Ay=9

Ay=9/5

sum of vertical forces =0

Ay+By+1=0

By=-1-Ay

=-1-9/5

=-14/5

(B) -14/5

ReplyDeleteA) -9/5

ReplyDeleteB

ReplyDeleteBy = ((Mab-Mba)/Lab) + ((Mcb-Mbc)/Lbc))

ReplyDelete= ((0-9)/5)) + ((5-9)/4)

=-9/5 + -1

=-9/5+-5/5

=-14/5

A) 9/5

ReplyDelete